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X^2+(5X+4)=180
We move all terms to the left:
X^2+(5X+4)-(180)=0
We get rid of parentheses
X^2+5X+4-180=0
We add all the numbers together, and all the variables
X^2+5X-176=0
a = 1; b = 5; c = -176;
Δ = b2-4ac
Δ = 52-4·1·(-176)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-27}{2*1}=\frac{-32}{2} =-16 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+27}{2*1}=\frac{22}{2} =11 $
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